【CodinGame】趣味算法 CLASH OF CODE -20240722

简单判断

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

b = int(input())
p = int(input())
r = int(input())
t = int(input())

if p*r*t < b:
    print("Enough bread")
if p*r*t == b:
    print("Just enough bread")
if p*r*t > b:
    print("Not enough bread")

计算2的幂总和

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

n = int(input())

# 计算2的幂总和
print(sum([2**i for i in range(n)]))

ascii求和

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

line = input()
sum_count = 0

for i in line:
    # 计算ascii
    sum_count += ord(i)

print(int(math.sqrt(sum_count)))

奇偶数索引

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

n = input()
ou_count = 0
ji_count = 0

for i , num in enumerate(n):
    if int(num)%2==0:
        ou_count += i
    else:
        ji_count += i

print(abs(ou_count - ji_count))

更优雅的写法（作者：norxondor_gorgonax）

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

n = input()


print(abs(sum(map(int, n[::2])) - sum(map(int, n[1::2]))))

大小写字母

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

s = input()

# 大写字母的数量
print(sum(1 for c in s if c.isupper()) ** sum(1 for c in s if c.islower()))

优雅写法(作者：norxondor_gorgonax)

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

s = input()

# Write an answer using print
# To debug: print("Debug messages...", file=sys.stderr, flush=True)

print(sum(map(str.isupper, s)) ** sum(map(str.islower, s)))

两数互质

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

a = int(input())
b = int(input())

# 给定两个整数 a 和 b。对于这两个整数，我们寻找能除以 a 和 b 的正整数（不留余数）。如果除了 1 之外不存在这样的整数，我们称 a 和 b 互质。
print('true' if math.gcd(a, b) == 1 else 'false')

优雅（作者：norxondor_gorgonax）

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

a = int(input())
b = int(input())

# Write an answer using print
# To debug: print("Debug messages...", file=sys.stderr, flush=True)

print(str(math.gcd(a,b)==1).lower())

chr

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

n = int(input())

# 1对应A，拿到对应字符
print(chr(64 + n)*n)

这里注意chr 是 Python 中的一个内置函数，用于将一个整数（通常是一个 Unicode 码点）转换为其对应的字符

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